Exercise 1
Heirs | 2 Daughters | Mother | Father |
Shares | 2/3 | 1/6 | 1/6 + residue |
Base number | 6 | ||
Portions | Each daughter = 2 | 1 | 1 |
Note that brother and sister are excluded by father.
2 daughters: 6 × 2/3 = 4 portions. Each daughter inherits 2.
Mother: 6 × 1/6 = 1 portion
Father: 6 × 1/6 = 1 portion
Check for residue: 6 – 4 – 1 – 1 = 0 or 6 – (4 + 1 + 1) = 0
Since there is no residue, the father receives just 1 portion like the mother.
Exercise 2
Heirs | 2 Wives | 5 Daughters | 3 Full brothers |
Shares | 1/8 | 2/3 | Residue |
Base number | 8 x 3 = 24 | ||
Portions | 3 | 16 | 5 |
New base number | 2 x 5 x 3 x 24 = 720 | ||
New portions | Each = 45 | Each = 96 | Each = 50 |
None of the three categories of heirs can share their portions. So let’s consider the relationship between their number of heads and number of portions.
“Wives” category: 2 and 3 are tabayin (parallel)
“Daughters” category: 5 and 16 are tabayin (parallel)
“Full brothers” category: 3 and 5 are tabayin (parallel)
Since all of them are parallel, their number of heads is considered. Taking wives and daughters first, 2 and 5 are tabayin, so multiply them. 2 × 5 = 10. Now what is the relationship between 10 and 3 (heads of full brothers)? Tabayin. Again, multiply them. 10 × 3 = 30.
Hence, new base number = 30 × 24 = 720
New portion of 2 wives: 720 × 1/8 = 90; each has 45
New portion of 5 daughters: 720 × 2/3 = 480; each is given 96
New portion of 3 full brothers: 720 – (90 + 480) = 150; each inherits 50.
Exercise 3
a) 1/6 of the estate
Heirs | Husband | 2 Daughters | Mother | Grandfather | Full brother |
Shares | ¼ | 2/3 | 1/6 | 1/6 | Residue |
Base number | 12 | ||||
Portions | 3 | 8 | 2 | 2 | 0 |
Increased base number | 15 | ||||
Values | 0.2 | 0.53 | 0.13 | 0.13 | 0 |
b) 1/3 of residue
Heirs | Husband | 2 Daughters | Mother | Grandfather | Full brother |
Shares | ¼ | 2/3 | 1/6 | Residue | |
Base number | 12 | ||||
Portions | 3 | 8 | 2 | 0 | |
Increased base number | 13 | ||||
Values | 0.23 | 0.62 | 0.15 | 0 | 0 |
There is no residue, so 1/3 of residue does not exist. Hence, grandfather and full brother inherits nothing.
c) Muqasama
Here, grandfather is expected to share the residue with full brother. But from the table above, there will be no residue to share. Hence grandfather and full brother gets nothing. Therefore, 1/6 of the estate is the most favourable to grandfather. The two other options do not entitle him to any share of the estate.
Quick links
- Introduction
- Male heirs
- Female heirs
- Non heirs
- Impediments to inheritance
- Exclusion
- Exclusion – Part 2
- Exclusion – Part 3
- Partial exclusion
- Note on difference of opinion
- Inheritance of children
- Inheritance of spouses
- Inheritance of parents
- Inheritance of grandparents
- Inheritance of siblings
- Residuaries (‘Asabah)
- Partial exclusion
- Inheritance arithmetic (“inherithmetic”)
- Procedure of solving inheritance problems
- Levels of inheritance problems (Level one)
- Level one – continued
- Lowest Common Multiple (LCM)
- Highest Common Factor (HCF)
- Prime numbers
- Increment of base number (‘Awl)
- Level two – Part 1
- Level two – Part 2
- Level two – Part 3
- Level two – Part 4
- Level three
- Inheritance of grandfather along with siblings
- Inheritance of grandfather along with siblings in the presence of other heirs
- Special cases
- Summary of rules
- Further reading
- YOU ARE HERE: Solutions to exercises
Your Questions, Our Answers
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